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5y=3y^2+4
We move all terms to the left:
5y-(3y^2+4)=0
We get rid of parentheses
-3y^2+5y-4=0
a = -3; b = 5; c = -4;
Δ = b2-4ac
Δ = 52-4·(-3)·(-4)
Δ = -23
Delta is less than zero, so there is no solution for the equation
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